What are the solutions to the equation 3x^2-12x+39=0 ?

The solutions to the equation 3x^2-12x+39=0 are x=2+3i,x=2-3i

Find the zeros of 3x^2-12x+39=0

The zeros of 3x^2-12x+39=0 are x=2+3i,x=2-3i

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3 x^{2} - 12 x + 39 = 0

x = 2 + 3 i, x = 2 - 3 i

Solution steps

3 x^{2} - 12 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 39}{2 \cdot 3}

Simplify

(- 12)^{2} - 4 \cdot 3 \cdot 39 : 18 i

x_{1, 2} = \frac{- ( - 12 ) \pm 18 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 18 i}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 18 i}{2 \cdot 3}

x = \frac{- ( - 12 ) + 18 i}{2 \cdot 3} : 2 + 3 i

x = \frac{- ( - 12 ) - 18 i}{2 \cdot 3} : 2 - 3 i

The solutions to the quadratic equation are:

x = 2 + 3 i, x = 2 - 3 i

25 6^{\frac{1}{3}} \cdot 2^{\frac{1}{3}}

\frac{w}{24} - \frac{5}{6} = \frac{7}{12}

- 5 (2 x + 1) - 2 x - 2 = 17

2 (2) - 2

5 (x + 1) - x = 3 (x - 1) + 7

What are the solutions to the equation 3x^2-12x+39=0 ?
The solutions to the equation 3x^2-12x+39=0 are x=2+3i,x=2-3i
Find the zeros of 3x^2-12x+39=0
The zeros of 3x^2-12x+39=0 are x=2+3i,x=2-3i