What is expand f(x)(x=x^2-cos(2x-2)) ?

The solution to expand f(x)(x=x^2-cos(2x-2)) is xf(x)=x^2-cos(2x-2)f(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand f(x)(x=x^2-cos(2x-2))

expand

f (x) (x = x^{2} - cos (2 x - 2))

x f (x) = x^{2} - cos (2 x - 2) f (x)

Solution steps

f (x) (x = x^{2} - cos (2 x - 2))

= f (x) (= x^{2} x - cos (2 x - 2))

Apply the distributive law:

a (b - c) = ab - a c

a = f (x), b = x = x^{2}, c = cos (2 x - 2)

f (x) x = x^{2} - f (x) cos (2 x - 2)

x f (x) = x^{2} - cos (2 x - 2) f (x)

\frac{( x - b ) ^{2}}{x ^{3}}

n (n - 3 n^{2} = 2)

\frac{3}{4 ( 12 v + 16 )}

\frac{( 2 x ^{3} + 3 ) ^{6}}{x ^{12}}

(A + Bt) e^{s t}

What is expand f(x)(x=x^2-cos(2x-2)) ?
The solution to expand f(x)(x=x^2-cos(2x-2)) is xf(x)=x^2-cos(2x-2)f(x)