What are the solutions to the equation x^2=-15x ?

The solutions to the equation x^2=-15x are x=0,x=-15

Find the zeros of x^2=-15x

The zeros of x^2=-15x are x=0,x=-15

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x^{2} = - 15 x

x = 0, x = - 15

Solution steps

x^{2} = - 15 x

Move

15 x

to the left side

x^{2} + 15 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 0 = 15

x_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 15}{2 \cdot 1}, x_{2} = \frac{- 15 - 15}{2 \cdot 1}

x = \frac{- 15 + 15}{2 \cdot 1} : 0

x = \frac{- 15 - 15}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 0, x = - 15

\frac{7 ^{- 2}}{2 ^{- 3}}

- 12 x^{2} + 5 x + 7 \leq 5

r - 11 = 5

7 a x - 21 x + 12 - 4 a + 4 x y - 6 y + 15 - 10 x

5 (x + 1) - 4 x \geq - 9

What are the solutions to the equation x^2=-15x ?
The solutions to the equation x^2=-15x are x=0,x=-15
Find the zeros of x^2=-15x
The zeros of x^2=-15x are x=0,x=-15