What is expand l(e^t+1)h(t-2) ?

The solution to expand l(e^t+1)h(t-2) is le^tth-2le^th+lth-2lh

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expand l(e^t+1)h(t-2)

expand

l (e^{t} + 1) h (t - 2)

l e^{t} t h - 2 l e^{t} h + lt h - 2 l h

Solution steps

l (e^{t} + 1) h (t - 2)

= l h (e^{t} + 1) (t - 2)

Expand

(e^{t} + 1) (t - 2) : e^{t} t - 2 e^{t} + t - 2

= l h (e^{t} t - 2 e^{t} + t - 2)

Expand

l h (e^{t} t - 2 e^{t} + t - 2) : l e^{t} t h - 2 l e^{t} h + lt h - 2 l h

= l e^{t} t h - 2 l e^{t} h + lt h - 2 l h

(\frac{π}{2} + 2) r

2 π (81 h - h^{3})

x (1 + 23) - 3 - 63

(- 82) + (- 30)

\frac{( ( x - d ) 2 - x ^{2} )}{d}

What is expand l(e^t+1)h(t-2) ?
The solution to expand l(e^t+1)h(t-2) is le^tth-2le^th+lth-2lh