What is expand pi^{e^1}-arccos(1) ?

The solution to expand pi^{e^1}-arccos(1) is pi^e

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expand pi^{e^1}-arccos(1)

expand

π^{e^{1}} - arccos (1)

π^{e}

Decimal Notation

22.45915 \dots

Solution steps

π^{e^{1}} - arccos (1)

Apply rule

a^{1} = a

e^{1} = e

= π^{e} - arccos (1)

Use the following trivial identity:

arccos (1) = 0

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π^{e} - 0

π^{e} - 0 = π^{e}

= π^{e}

cos (\frac{π}{2} \cdot (x + 1))

(e^{i wt} + e^{- i wt}) e^{- i wt}

\frac{7 ( a + h ) - 6}{( a + h ) - 8}

\frac{5 ( x + 2 )}{2 x - 14}

y (2 x + 3 y = - 2)

What is expand pi^{e^1}-arccos(1) ?
The solution to expand pi^{e^1}-arccos(1) is pi^e