What is expand (2x-3x^2)(7x^3-3x)' ?

The solution to expand (2x-3x^2)(7x^3-3x)' is 2x(7x^3-3x)'-3x^2(7x^3-3x)'

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expand (2x-3x^2)(7x^3-3x)'

expand

(2 x - 3 x^{2}) (7 x^{3} - 3 x)^{'}

2 x (7 x^{3} - 3 x)' - 3 x^{2} (7 x^{3} - 3 x)'

Solution steps

(2 x - 3 x^{2}) (7 x^{3} - 3 x)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (7 x^{3} - 3 x)^{'}, b = 2 x, c = 3 x^{2}

= (7 x^{3} - 3 x)^{^{'}} 2 x - (7 x^{3} - 3 x)^{^{'}} 3 x^{2}

= 2 x (7 x^{3} - 3 x)^{^{'}} - 3 x^{2} (7 x^{3} - 3 x)^{^{'}}

(e^{i 2 t} + e^{- i 2 t})^{2}

6 x^{2} + 3 x - 9 - 2 x^{2} + 4 x - 1

sin (π x) - π x (1 - x)

\frac{2 ( x + y )}{y}

\frac{( x + 2 ) ^{2}}{x ^{2}}

What is expand (2x-3x^2)(7x^3-3x)' ?
The solution to expand (2x-3x^2)(7x^3-3x)' is 2x(7x^3-3x)'-3x^2(7x^3-3x)'