What is expand (2x+sin(3x))dx ?

The solution to expand (2x+sin(3x))dx is 2xdx+sin(3x)dx

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expand (2x+sin(3x))dx

expand

(2 x + sin (3 x)) d x

2 x d x + sin (3 x) d x

Solution steps

(2 x + sin (3 x)) d x

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = 2 x, c = sin (3 x)

= d x \cdot 2 x + d x sin (3 x)

= 2 x d x + sin (3 x) d x

\frac{( 1 + x ) ^{2}}{2 - x}

\frac{1}{( a + 4 ) ^{2}}

se x (1 + cos (x))

y (y + 7 = 18)

d x (2 R x - x^{2})

What is expand (2x+sin(3x))dx ?
The solution to expand (2x+sin(3x))dx is 2xdx+sin(3x)dx