What is expand l(t^2+2e^{-2t}) ?

The solution to expand l(t^2+2e^{-2t}) is lt^2+2le^{-2t}

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expand l(t^2+2e^{-2t})

expand

l (t^{2} + 2 e^{- 2 t})

l t^{2} + 2 l e^{- 2 t}

Solution steps

l (t^{2} + 2 e^{- 2 t})

Apply the distributive law:

a (b + c) = ab + a c

a = l, b = t^{2}, c = 2 e^{- 2 t}

= l t^{2} + l \cdot 2 e^{- 2 t}

= l t^{2} + 2 l e^{- 2 t}

\frac{x - 5}{x ( x - 1 ) ( x + 3 )}

- 2 (x^{2} = 3 x - 7) - 11

\frac{1}{s ( s - 1 ) ( s ^{2} - 4 )}

\frac{( x + 2 ) ( x - 3 )}{x - 1}

B (2 x (3 x - 7))

What is expand l(t^2+2e^{-2t}) ?
The solution to expand l(t^2+2e^{-2t}) is lt^2+2le^{-2t}