What is expand 2(x^2e^{-2x}+xe^{-2x}) ?

The solution to expand 2(x^2e^{-2x}+xe^{-2x}) is 2e^{-2x}x^2+2e^{-2x}x

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expand 2(x^2e^{-2x}+xe^{-2x})

expand

2 (x^{2} e^{- 2 x} + x e^{- 2 x})

2 e^{- 2 x} x^{2} + 2 e^{- 2 x} x

Solution steps

2 (x^{2} e^{- 2 x} + x e^{- 2 x})

= 2 (e^{- 2 x} x^{2} + e^{- 2 x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = x^{2} e^{- 2 x}, c = x e^{- 2 x}

= 2 x^{2} e^{- 2 x} + 2 x e^{- 2 x}

= 2 e^{- 2 x} x^{2} + 2 e^{- 2 x} x

\frac{( 2 b - 22 ) ^{2}}{12}

\frac{s ^{3}}{( s + w ) ^{2}}

8 \times (6 - 10.2)

(x^{3} + 2 x) (e^{x})

(tan (x) - x + C) d x

What is expand 2(x^2e^{-2x}+xe^{-2x}) ?
The solution to expand 2(x^2e^{-2x}+xe^{-2x}) is 2e^{-2x}x^2+2e^{-2x}x