What is expand (1-cos(3t-3))/((t-1)^2) ?

The solution to expand (1-cos(3t-3))/((t-1)^2) is (1-cos(3t-3))/(t^2-2t+1)

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expand (1-cos(3t-3))/((t-1)^2)

expand

\frac{1 - cos ( 3 t - 3 )}{( t - 1 ) ^{2}}

\frac{1 - cos ( 3 t - 3 )}{t ^{2} - 2 t + 1}

Solution steps

\frac{1 - cos ( 3 t - 3 )}{( t - 1 ) ^{2}}

(t - 1)^{2} = t^{2} - 2 t + 1

= \frac{1 - cos ( 3 t - 3 )}{t ^{2} - 2 t + 1}

\frac{12}{( x + 3 ) ^{2}}

co nj ug a d os (5 h + 3) (4 h - 5)

(y = 4,) (z = - 2)

(a^{^{'}} + b) c + ab c

\frac{z - 5}{( z ^{2} - 10 z + 24 ) ^{2}}

What is expand (1-cos(3t-3))/((t-1)^2) ?
The solution to expand (1-cos(3t-3))/((t-1)^2) is (1-cos(3t-3))/(t^2-2t+1)