What is expand ((x-1)*2^{x+1})*2.5 ?

The solution to expand ((x-1)*2^{x+1})*2.5 is 2.5*2^{x+1}x-2.5*2^{x+1}

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expand ((x-1)2^{x+1})2.5

expand

((x - 1) \cdot 2^{x + 1}) \cdot 2.5

2.5 \cdot 2^{x + 1} x - 2.5 \cdot 2^{x + 1}

Solution steps

((x - 1) \cdot 2^{x + 1}) \cdot 2.5

Remove parentheses:

(a) = a

= (x - 1) \cdot 2^{x + 1} \cdot 2.5

= 2.5 \cdot 2^{x + 1} (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = 2^{x + 1} \cdot 2.5, b = x, c = 1

= 2^{x + 1} \cdot 2.5 x - 2^{x + 1} \cdot 2.5 \cdot 1

= 2.5 \cdot 2^{x + 1} x - 1 \cdot 2.5 \cdot 2^{x + 1}

Multiply the numbers:

1 \cdot 2.5 = 2.5

= 2.5 \cdot 2^{x + 1} x - 2.5 \cdot 2^{x + 1}

(- 1, - 3) y (2, - 2)

so l v e (3 x^{2} + 6 x = 0)

\frac{( m - n ) ^{2} + 6 ( m - n )}{9}

\frac{2}{s ^{3} ( s + 1 )}

\frac{e ^{- m}}{( 1 + e ^{- m} ) ^{2}}

What is expand ((x-1)*2^{x+1})*2.5 ?
The solution to expand ((x-1)*2^{x+1})*2.5 is 2.5*2^{x+1}x-2.5*2^{x+1}