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Popular >

simplify e^{-ln(y^a)}

Solution

simplify

e^{- l n (y^{a})}

Solution

\frac{1}{y ^{a}}

Solution steps

e^{- l n (y^{a})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (y^{a})}}

e^{l n (y^{a})} = y^{a}

= \frac{1}{y ^{a}}

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Frequently Asked Questions (FAQ)

What is e^{-ln(y^a)} ?
The solution to e^{-ln(y^a)} is 1/(y^a)