What is sqrt((\sqrt[3]{1+x^4))} ?

The solution to sqrt((\sqrt[3]{1+x^4))} is \sqrt[6]{x^4+1}

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simplify sqrt((\sqrt[3]{1+x^4))}

simplify

Solution steps

Apply radical rule:

= ((1 + x^{4})^{\frac{1}{3}})^{\frac{1}{2}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (1 + x^{4})^{\frac{1}{3} \cdot \frac{1}{2}}

\frac{1}{3} \cdot \frac{1}{2} = \frac{1}{6}

= (1 + x^{4})^{\frac{1}{6}}

x^{7} (x^{2} y)

90 e^{- (0.021661) (12)}

\frac{w - 5}{w + 5}

3.67 \cdot 1 0^{- 1}

What is sqrt((\sqrt[3]{1+x^4))} ?
The solution to sqrt((\sqrt[3]{1+x^4))} is \sqrt[6]{x^4+1}