What are the solutions to the equation 3(x+9)^2=12 ?

The solutions to the equation 3(x+9)^2=12 are x=-7,x=-11

Find the zeros of 3(x+9)^2=12

The zeros of 3(x+9)^2=12 are x=-7,x=-11

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3 (x + 9)^{2} = 12

x = - 7, x = - 11

Solution steps

3 (x + 9)^{2} = 12

Divide both sides by

3

(x + 9)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 4 : x = - 7

Solve

x + 9 = - 4 : x = - 11

The solutions to the quadratic equation are:

x = - 7, x = - 11

245 - 25

3 x^{2} - 5 x - 1 = 0

∣ 3 r + 5 ∣ = ∣ 7 r - 25 ∣

3 x - 2 \leq 7

2 (3 x - 2) - x + 3 = x - 2

What are the solutions to the equation 3(x+9)^2=12 ?
The solutions to the equation 3(x+9)^2=12 are x=-7,x=-11
Find the zeros of 3(x+9)^2=12
The zeros of 3(x+9)^2=12 are x=-7,x=-11