What is (1.6*10^{-19})(3712) ?

The solution to (1.6*10^{-19})(3712) is (29)/(5^{20)*512}

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simplify (1.6*10^{-19})(3712)

simplify

(1.6 \cdot 1 0^{- 19}) (3712)

\frac{29}{5 ^{20} \cdot 512}

Decimal Notation

5.9392 E - 16

Solution steps

(1.6 \cdot 1 0^{- 19}) (3712)

Apply rule:

(a) = a

(3712) = 3712

= 1.6 \cdot 1 0^{- 19} \cdot 3712

Multiply the numbers:

1.6 \cdot 3712 = 5939.2

= 5939.2 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 5939.2

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 5939.2

\frac{1}{1 0 ^{19}} \cdot 5939.2 = \frac{5939.2}{1 0 ^{19}}

= \frac{5939.2}{1 0 ^{19}}

\frac{5939.2}{1 0 ^{19}} = \frac{59392}{10 \cdot 1 0 ^{19}}

= \frac{59392}{10 \cdot 1 0 ^{19}}

10 \cdot 1 0^{19} = 1 0^{20}

= \frac{59392}{1 0 ^{20}}

Factor

59392 : 2^{11} \cdot 29

= \frac{2 ^{11} \cdot 29}{1 0 ^{20}}

Factor

1 0^{20} : 2^{20} \cdot 5^{20}

= \frac{2 ^{11} \cdot 29}{2 ^{20} \cdot 5 ^{20}}

\frac{2 ^{11}}{2 ^{20}} = \frac{1}{2 ^{9}}

= \frac{29}{2 ^{9} \cdot 5 ^{20}}

2^{9} = 512

= \frac{29}{5 ^{20} \cdot 512}

e^{- 2 l n (x + 1)}

(5 a^{4} b^{3}) (7 a b^{6})

(3 x 1 0^{6}) (2.3 x 1 0^{5})

n + 1 \cdot n

What is (1.6*10^{-19})(3712) ?
The solution to (1.6*10^{-19})(3712) is (29)/(5^{20)*512}