What is (1+sin(2pix))e^{-x/(10)} ?

The solution to (1+sin(2pix))e^{-x/(10)} is (sin(2pix)+1)/(e^{x/(10))}

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simplify (1+sin(2pix))e^{-x/(10)}

simplify

(1 + sin (2 π x)) e^{- \frac{x}{10}}

\frac{sin ( 2 π x ) + 1}{e ^{\frac{x}{10}}}

Solution steps

(1 + sin (2 π x)) e^{- \frac{x}{10}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{x}{10}}} (sin (2 π x) + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 + sin ( 2 π x ) )}{e ^{\frac{x}{10}}}

1 \cdot (1 + sin (2 π x)) = 1 + sin (2 π x)

= \frac{1 + sin ( 2 π x )}{e ^{\frac{x}{10}}}

(3 a^{3} b^{3}) (16 a^{2} b^{4})

(2 x^{2} y^{3}) (3 x z^{2}) (5 y)

e^{- 0.46209 \cdot 16}

(1 - x^{2})^{x}

1.3 e^{- 0.3 (3.8)}

What is (1+sin(2pix))e^{-x/(10)} ?
The solution to (1+sin(2pix))e^{-x/(10)} is (sin(2pix)+1)/(e^{x/(10))}