What are the solutions to the equation x^2+4x=7 ?

The solutions to the equation x^2+4x=7 are x=-2+sqrt(11),x=-2-sqrt(11)

Find the zeros of x^2+4x=7

The zeros of x^2+4x=7 are x=-2+sqrt(11),x=-2-sqrt(11)

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x^{2} + 4 x = 7

x = - 2 + 11, x = - 2 - 11

Decimal Notation

x = 1.31662 \dots, x = - 5.31662 \dots

Solution steps

x^{2} + 4 x = 7

Move

7

to the left side

x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 7) = 211

x_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 11}{2 \cdot 1}

x = \frac{- 4 + 2 11}{2 \cdot 1} : - 2 + 11

x = \frac{- 4 - 2 11}{2 \cdot 1} : - 2 - 11

The solutions to the quadratic equation are:

x = - 2 + 11, x = - 2 - 11

10 x - 4 \geq 10 x - 7 or 7 - 7 x \geq - 4 x + 4

8 ∣ - 4 + 3 n ∣ - 2 = 14

\frac{( 7 + 2 i ) ( 8 - i )}{2 + i}

x^{2} x^{\frac{1}{2}}

6 x^{2} - 3 = 0

What are the solutions to the equation x^2+4x=7 ?
The solutions to the equation x^2+4x=7 are x=-2+sqrt(11),x=-2-sqrt(11)
Find the zeros of x^2+4x=7
The zeros of x^2+4x=7 are x=-2+sqrt(11),x=-2-sqrt(11)