What is (7.78x10^{-11})(5.9x10^{-18}) ?

The solution to (7.78x10^{-11})(5.9x10^{-18}) is (45.902x^2)/(10^{29)}

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simplify (7.78x10^{-11})(5.9x10^{-18})

simplify

(7.78 x 1 0^{- 11}) (5.9 x 1 0^{- 18})

\frac{45.902 x ^{2}}{1 0 ^{29}}

Solution steps

(7.78 x \cdot 1 0^{- 11}) (5.9 x \cdot 1 0^{- 18})

Simplify

7.78 x \cdot 1 0^{- 11} : \frac{7.78 x}{1 0 ^{11}}

= \frac{7.78 x}{1 0 ^{11}} \cdot 5.9 x \cdot 1 0^{- 18}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= \frac{7.78 x}{1 0 ^{11}} \cdot 5.9 x \frac{1}{1 0 ^{18}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{7.78 x \cdot 5.9 x \cdot 1}{1 0 ^{11} \cdot 1 0 ^{18}}

Simplify

7.78 x \cdot 5.9 x \cdot 1 : 45.902 x^{2}

= \frac{45.902 x ^{2}}{1 0 ^{11} \cdot 1 0 ^{18}}

1 0^{11} \cdot 1 0^{18} = 1 0^{29}

= \frac{45.902 x ^{2}}{1 0 ^{29}}

3 e^{- 7}

3 t^{2} \cdot (2.4 \cdot t^{2})

5 - x x^{2} - 9

What is (7.78x10^{-11})(5.9x10^{-18}) ?
The solution to (7.78x10^{-11})(5.9x10^{-18}) is (45.902x^2)/(10^{29)}