What is 23.04*10^{-29} ?

The solution to 23.04*10^{-29} is 9/(5^{29)*209715200}

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simplify 23.04*10^{-29}

simplify

23.04 \cdot 1 0^{- 29}

\frac{9}{5 ^{29} \cdot 209715200}

Solution steps

23.04 \cdot 1 0^{- 29}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 29} = \frac{1}{1 0 ^{29}}

= 23.04 \cdot \frac{1}{1 0 ^{29}}

23.04 \cdot \frac{1}{1 0 ^{29}} = \frac{23.04}{1 0 ^{29}}

= \frac{23.04}{1 0 ^{29}}

\frac{23.04}{1 0 ^{29}} = \frac{2304}{100 \cdot 1 0 ^{29}}

= \frac{2304}{100 \cdot 1 0 ^{29}}

Factor the number:

2304 = 4 \cdot 576

= \frac{4 \cdot 576}{100 \cdot 1 0 ^{29}}

Factor the number:

100 = 4 \cdot 25

= \frac{4 \cdot 576}{4 \cdot 25 \cdot 1 0 ^{29}}

Cancel the common factor:

4

= \frac{576}{25 \cdot 1 0 ^{29}}

Factor

576 : 2^{6} \cdot 9

= \frac{2 ^{6} \cdot 9}{25 \cdot 1 0 ^{29}}

Factor

1 0^{29} : 2^{29} \cdot 5^{29}

= \frac{2 ^{6} \cdot 9}{25 \cdot 2 ^{29} \cdot 5 ^{29}}

\frac{2 ^{6}}{2 ^{29}} = \frac{1}{2 ^{23}}

= \frac{9}{25 \cdot 2 ^{23} \cdot 5 ^{29}}

25 \cdot 2^{23} \cdot 5^{29} = 5^{29} \cdot 209715200

= \frac{9}{5 ^{29} \cdot 209715200}

(\frac{1}{2} mn) (8 m^{2} n^{2})

5.6 \cdot 1 0^{- 2}

7.78 \cdot 1 0^{- 8}

2.33 \cdot 1 0^{- 3}