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Popular >

simplify y^{2+a}e^{-ln(y^a)}

Solution

simplify

y^{2 + a} e^{- l n (y^{a})}

Solution

y^{2}

Solution steps

y^{2 + a} e^{- l n (y^{a})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (y^{a})}} y^{a + 2}

\frac{1}{e ^{l n (y^{a})}} = \frac{1}{y ^{a}}

= \frac{1}{y ^{a}} y^{a + 2}

Simplify

= y^{2}

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Frequently Asked Questions (FAQ)

What is y^{2+a}e^{-ln(y^a)} ?
The solution to y^{2+a}e^{-ln(y^a)} is y^2