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Popular >

simplify e^{-ln(1+t^2)}

Solution

simplify

e^{- l n (1 + t^{2})}

Solution

\frac{1}{t ^{2} + 1}

Solution steps

e^{- l n (1 + t^{2})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (1 + t^{2})}}

e^{l n (1 + t^{2})} = 1 + t^{2}

= \frac{1}{1 + t ^{2}}

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Frequently Asked Questions (FAQ)

What is e^{-ln(1+t^2)} ?
The solution to e^{-ln(1+t^2)} is 1/(t^2+1)