What is e^{-5/2 ln(10-2t)} ?

The solution to e^{-5/2 ln(10-2t)} is 1/((-2t+10)^{5/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-5/2 ln(10-2t)}

simplify

e^{- \frac{5}{2} l n (10 - 2 t)}

\frac{1}{( - 2 t + 10 ) ^{\frac{5}{2}}}

Solution steps

e^{- \frac{5}{2} l n (10 - 2 t)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{5}{2} l n (- 2 t + 10)}}

e^{\frac{5}{2} l n (10 - 2 t)} = (10 - 2 t)^{\frac{5}{2}}

= \frac{1}{( 10 - 2 t ) ^{\frac{5}{2}}}

x^{4 a + 16}

3.21 x 1 0^{- 4}

- e^{2} \cdot e^{2}

e^{t^{2}} \cdot e^{t^{2}}

3.3 \cdot 1 0^{- 5} \cdot 12000

What is e^{-5/2 ln(10-2t)} ?
The solution to e^{-5/2 ln(10-2t)} is 1/((-2t+10)^{5/2)}