What is (x^2+y)^2(x^2-y)^2 ?

The solution to (x^2+y)^2(x^2-y)^2 is (x^2+y)^2(x^2-y)^2

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simplify (x^2+y)^2(x^2-y)^2

simplify

(x^{2} + y)^{2} (x^{2} - y)^{2}

(x^{2} + y)^{2} (x^{2} - y)^{2}

Solution steps

(x^{2} + y)^{2} (x^{2} - y)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + y)^{2} (x^{2} - y)^{2} = ((x^{2} + y) (x^{2} - y))^{2}

= ((x^{2} + y) (x^{2} - y))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} + y)^{2} (x^{2} - y)^{2}

(7.2 \cdot 1 0^{- 3}) \cdot 1000

2.5 \cdot (5 \cdot 1 0^{- 3})

e^{- x} (2 e^{x} + e^{2 x})

What is (x^2+y)^2(x^2-y)^2 ?
The solution to (x^2+y)^2(x^2-y)^2 is (x^2+y)^2(x^2-y)^2