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Popular >

simplify e^{-ln|x^2+1|}

Solution

simplify

e^{- l n ∣ x^{2} + 1 ∣}

Solution

\frac{1}{∣ x ^{2} + 1 ∣}

Solution steps

e^{- l n ∣ x^{2} + 1 ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n ∣ x^{2} + 1 ∣}}

e^{l n ∣ x^{2} + 1 ∣} = x^{2} + 1

= \frac{1}{∣ x ^{2} + 1 ∣}

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1.93 \cdot 1 0^{- 3}

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Frequently Asked Questions (FAQ)

What is e^{-ln|x^2+1|} ?
The solution to e^{-ln|x^2+1|} is 1/(|x^2+1|)