What is P^1(1,3,5)P^2(2,-1,4) ?

The solution to P^1(1,3,5)P^2(2,-1,4) is (1*3*5,,)(2,-1*4,)P^3

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simplify P^1(1,3,5)P^2(2,-1,4)

simplify

P^{1} (1, 3, 5) P^{2} (2, - 1, 4)

(1 \cdot 3 \cdot 5,,) (2, - 1 \cdot 4,) P^{3}

Solution steps

P^{1} (1, 3, 5) P^{2} (2, - 1, 4)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

P^{1} P^{2} = P^{1 + 2}

= (1, 3, 5) P^{1 + 2} (2, - 1, 4)

Add the numbers:

1 + 2 = 3

= (1, 3, 5) P^{3} (2, - 1, 4)

5 d^{2} e^{4} \cdot 2 e^{6}

(x + 4) (x - 3) (2 x - 1)

x^{u n d e f in e d}

\frac{3}{2 y}

a e^{- s t}

What is P^1(1,3,5)P^2(2,-1,4) ?
The solution to P^1(1,3,5)P^2(2,-1,4) is (1*3*5,,)(2,-1*4,)P^3