What is e^{-(-ln(1/6))^{0.5}} ?

The solution to e^{-(-ln(1/6))^{0.5}} is 1/(e^{ln^{1/2)(6)}}

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simplify e^{-(-ln(1/6))^{0.5}}

simplify

e^{- (- l n (\frac{1}{6}))^{0.5}}

\frac{1}{e ^{l n^{\frac{1}{2}} (6)}}

Decimal Notation

0.26222 \dots

Solution steps

e^{- (- l n (\frac{1}{6}))^{0.5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(- l n (\frac{1}{6}))^{0.5}}}

e^{(- l n (\frac{1}{6}))^{\frac{1}{2}}} = e^{l n^{\frac{1}{2}} (6)}

= \frac{1}{e ^{l n^{\frac{1}{2}} (6)}}

2.3 x 1 0^{- 2}

(3. 1^{5}) (8. 1^{- 4})

3 e^{2 x} \cdot e^{- x}

(3)^{x}

5.021 \cdot 1 0^{- 4}

What is e^{-(-ln(1/6))^{0.5}} ?
The solution to e^{-(-ln(1/6))^{0.5}} is 1/(e^{ln^{1/2)(6)}}