What are the solutions to the equation x^2-9x+24=0 ?

The solutions to the equation x^2-9x+24=0 are x= 9/2+i(sqrt(15))/2 ,x= 9/2-i(sqrt(15))/2

Find the zeros of x^2-9x+24=0

The zeros of x^2-9x+24=0 are x= 9/2+i(sqrt(15))/2 ,x= 9/2-i(sqrt(15))/2

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x^{2} - 9 x + 24 = 0

x = \frac{9}{2} + i \frac{15}{2}, x = \frac{9}{2} - i \frac{15}{2}

Solution steps

x^{2} - 9 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 24 : 15 i

x_{1, 2} = \frac{- ( - 9 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 15 i}{2 \cdot 1}

x = \frac{- ( - 9 ) + 15 i}{2 \cdot 1} : \frac{9}{2} + i \frac{15}{2}

x = \frac{- ( - 9 ) - 15 i}{2 \cdot 1} : \frac{9}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{15}{2}, x = \frac{9}{2} - i \frac{15}{2}

- x \leq 2

x (m + 5) + 7 (m + 5)

5 - x = 6

\frac{x}{5} = 3

n^{2} + 3 n - 4

What are the solutions to the equation x^2-9x+24=0 ?
The solutions to the equation x^2-9x+24=0 are x= 9/2+i(sqrt(15))/2 ,x= 9/2-i(sqrt(15))/2
Find the zeros of x^2-9x+24=0
The zeros of x^2-9x+24=0 are x= 9/2+i(sqrt(15))/2 ,x= 9/2-i(sqrt(15))/2