What is expand 5(x^2-x-6)^{-1} ?

The solution to expand 5(x^2-x-6)^{-1} is 5/(x^2-x-6)

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expand 5(x^2-x-6)^{-1}

expand

5 (x^{2} - x - 6)^{- 1}

\frac{5}{x ^{2} - x - 6}

Solution steps

5 (x^{2} - x - 6)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 5 \cdot \frac{1}{( x ^{2} - x - 6 )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5}{x ^{2} - x - 6}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{5}{x ^{2} - x - 6}

6.21 \cdot 1 0^{- 6}

- 0.0078 e^{- 0.00012 \cdot 1}

e^{- 45}

50 \cdot 2. 7^{- 30 k}

What is expand 5(x^2-x-6)^{-1} ?
The solution to expand 5(x^2-x-6)^{-1} is 5/(x^2-x-6)