What are the solutions to the equation (t^2)/2+4t+5=0 ?

The solutions to the equation (t^2)/2+4t+5=0 are t=-4+sqrt(6),t=-4-sqrt(6)

Find the zeros of (t^2)/2+4t+5=0

The zeros of (t^2)/2+4t+5=0 are t=-4+sqrt(6),t=-4-sqrt(6)

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\frac{t ^{2}}{2} + 4 t + 5 = 0

t = - 4 + 6, t = - 4 - 6

Solution steps

\frac{t ^{2}}{2} + 4 t + 5 = 0

Multiply both sides by

2

t^{2} + 8 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 10 = 26

t_{1, 2} = \frac{- 8 \pm 2 6}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 8 + 2 6}{2 \cdot 1}, t_{2} = \frac{- 8 - 2 6}{2 \cdot 1}

t = \frac{- 8 + 2 6}{2 \cdot 1} : - 4 + 6

t = \frac{- 8 - 2 6}{2 \cdot 1} : - 4 - 6

The solutions to the quadratic equation are:

t = - 4 + 6, t = - 4 - 6

(- 2 + - 8) + (5 - - 50)

2 x^{2} + 5 x = 4

12 x^{2} - 7 x - 12

350 - 272 + 24

(\frac{7}{9})^{- 2}

What are the solutions to the equation (t^2)/2+4t+5=0 ?
The solutions to the equation (t^2)/2+4t+5=0 are t=-4+sqrt(6),t=-4-sqrt(6)
Find the zeros of (t^2)/2+4t+5=0
The zeros of (t^2)/2+4t+5=0 are t=-4+sqrt(6),t=-4-sqrt(6)