What is 12e^{-3(t-4)}u^{(t-4)} ?

The solution to 12e^{-3(t-4)}u^{(t-4)} is (12u^{t-4})/(e^{3(t-4))}

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simplify 12e^{-3(t-4)}u^{(t-4)}

simplify

12 e^{- 3 (t - 4)} u^{(t - 4)}

\frac{12 u ^{t - 4}}{e ^{3 (t - 4)}}

Solution steps

12 e^{- 3 (t - 4)} u^{(t - 4)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 12 \cdot \frac{1}{e ^{3 (t - 4)}} u^{t - 4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 12 u ^{t - 4}}{e ^{3 (t - 4)}}

Multiply the numbers:

1 \cdot 12 = 12

= \frac{12 u ^{t - 4}}{e ^{3 (t - 4)}}

- 4 e^{- 4 x}

\frac{1}{2} \cdot e^{- 0.25}

\frac{5}{7 z}

x x + 7

What is 12e^{-3(t-4)}u^{(t-4)} ?
The solution to 12e^{-3(t-4)}u^{(t-4)} is (12u^{t-4})/(e^{3(t-4))}