What are the solutions to the equation 3x^2+x-1/2 =0 ?

The solutions to the equation 3x^2+x-1/2 =0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

Find the zeros of 3x^2+x-1/2 =0

The zeros of 3x^2+x-1/2 =0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6

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3 x^{2} + x - \frac{1}{2} = 0

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

Decimal Notation

x = 0.27429 \dots, x = - 0.60762 \dots

Solution steps

3 x^{2} + x - \frac{1}{2} = 0

Multiply both sides by

2

6 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 1) = 27

x_{1, 2} = \frac{- 2 \pm 2 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 7}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 7}{2 \cdot 6}

x = \frac{- 2 + 2 7}{2 \cdot 6} : \frac{- 1 + 7}{6}

x = \frac{- 2 - 2 7}{2 \cdot 6} : - \frac{1 + 7}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{6}, x = - \frac{1 + 7}{6}

x^{4} - 5 x^{2} + 6

3 x - 7 \geq 4 x + 2

∣ x + 2 ∣ \geq 2

∣ 6 - 7 ∣

x^{3} + 7 x^{2} - 25 x - 175

What are the solutions to the equation 3x^2+x-1/2 =0 ?
The solutions to the equation 3x^2+x-1/2 =0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6
Find the zeros of 3x^2+x-1/2 =0
The zeros of 3x^2+x-1/2 =0 are x=(-1+sqrt(7))/6 ,x=-(1+sqrt(7))/6