What is e^{-(-ln(2/6))^{0.5}} ?

The solution to e^{-(-ln(2/6))^{0.5}} is 1/(e^{ln^{1/2)(3)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-(-ln(2/6))^{0.5}}

simplify

e^{- (- l n (\frac{2}{6}))^{0.5}}

\frac{1}{e ^{l n^{\frac{1}{2}} (3)}}

Decimal Notation

0.35058 \dots

Solution steps

e^{- (- l n (\frac{2}{6}))^{0.5}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(- l n (\frac{2}{6}))^{0.5}}}

e^{(- l n (\frac{2}{6}))^{\frac{1}{2}}} = e^{(- l n (\frac{1}{3}))^{\frac{1}{2}}}

= \frac{1}{e ^{(- l n (\frac{1}{3}))^{\frac{1}{2}}}}

e^{(- l n (\frac{1}{3}))^{\frac{1}{2}}} = e^{l n^{\frac{1}{2}} (3)}

= \frac{1}{e ^{l n^{\frac{1}{2}} (3)}}

\frac{1}{2} e^{- 2 (l n (4))}

6 x (m x^{m - 1})

(5 x^{2}) (3 x^{3})

6.4 \cdot 1 0^{- 2}

What is e^{-(-ln(2/6))^{0.5}} ?
The solution to e^{-(-ln(2/6))^{0.5}} is 1/(e^{ln^{1/2)(3)}}