What is \sqrt[3]{x^3+x^2-1}^2 ?

The solution to \sqrt[3]{x^3+x^2-1}^2 is (x^3+x^2-1)^{2/3}

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simplify \sqrt[3]{x^3+x^2-1}^2

simplify

(x^{3} + x^{2} - 1)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((x^{3} + x^{2} - 1)^{\frac{1}{3}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (x^{3} + x^{2} - 1)^{\frac{1}{3} \cdot 2}

\frac{1}{3} \cdot 2 = \frac{2}{3}

= (x^{3} + x^{2} - 1)^{\frac{2}{3}}

\frac{x}{x - 3}

\frac{0.0 8 ^{2}}{0.0 7 ^{2}}

\frac{6 ^{- 3000}}{6 ^{- 3000}}

(0.4 x^{5}) (0.9 x^{3})

e^{4 x - 2} e^{x + 1}

What is \sqrt[3]{x^3+x^2-1}^2 ?
The solution to \sqrt[3]{x^3+x^2-1}^2 is (x^3+x^2-1)^{2/3}