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Popular >

(|2x-1|)/(x+1)<= 2

Solution

\frac{∣ 2 x - 1 ∣}{x + 1} \leq 2

Solution

x < - 1 or x = \frac{1}{2}

+2

Interval Notation

(- \infty, - 1) \cup x = \frac{1}{2}

Decimal Notation

x < - 1 or x = 0.5

Solution steps

\frac{∣ 2 x - 1 ∣}{x + 1} \leq 2

Move

2

to the left side

\frac{∣ 2 x - 1 ∣}{x + 1} - 2 \leq 0

∣ 2 x - 1 ∣ \geq 0

If

\frac{a}{b} \leq 0 and a \geq 0

then

b < 0 or a = 0

x + 1 < 0 or ∣ 2 x - 1 ∣ = 0

x + 1 < 0 : x < - 1

∣ 2 x - 1 ∣ = 0 : x = \frac{1}{2}

Combine the intervals

x < - 1 or x = \frac{1}{2}

Popular Examples

10 = - 5 (x - 4)

simplify 20*1/1000*11*0.12*365/1 simplify

20 \cdot \frac{1}{1000} \cdot 11 \cdot 0.12 \cdot \frac{365}{1}

factor 3x^4-27x^3+60x^2 factor

3 x^{4} - 27 x^{3} + 60 x^{2}

20 \geq - 5 y

simplify (145)^{3/2}simplify

(145)^{\frac{3}{2}}

Frequently Asked Questions (FAQ)

What is (|2x-1|)/(x+1)<= 2 ?
The solution to (|2x-1|)/(x+1)<= 2 is x<-1\lor x= 1/2