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Popular >

simplify ((8/9)')^{-1}

Solution

simplify

((\frac{8}{9})^{'})^{- 1}

Solution

\frac{1}{( \frac{8}{9} ) '}

Solution steps

((\frac{8}{9})^{'})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( \frac{8}{9} ) ^{^{'}}}

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Frequently Asked Questions (FAQ)

What is ((8/9)')^{-1} ?
The solution to ((8/9)')^{-1} is 1/((8/9)')