What is 3x10^{-3}(0.005v^2+0.014v) ?

The solution to 3x10^{-3}(0.005v^2+0.014v) is (3x(0.005v^2+0.014v))/(1000)

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simplify 3x10^{-3}(0.005v^2+0.014v)

simplify

3 x 1 0^{- 3} (0.005 v^{2} + 0.014 v)

\frac{3 x ( 0.005 v ^{2} + 0.014 v )}{1000}

Solution steps

3 x \cdot 1 0^{- 3} (0.005 v^{2} + 0.014 v)

1 0^{- 3} = \frac{1}{1000}

= 3 x \frac{1}{1000} (0.005 v^{2} + 0.014 v)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 x \cdot 1 \cdot ( 0.005 v ^{2} + 0.014 v )}{1000}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3 x ( 0.005 v ^{2} + 0.014 v )}{1000}

0.67 \cdot 1 0^{- 6} m

(- 12.1) (1 - 54.07)^{- 2}

u - 1 u

(e^{- a t})^{2}

1.2 \cdot 1 0^{- 14}

What is 3x10^{-3}(0.005v^2+0.014v) ?
The solution to 3x10^{-3}(0.005v^2+0.014v) is (3x(0.005v^2+0.014v))/(1000)