What are the solutions to the equation -x^2+36=0 ?

The solutions to the equation -x^2+36=0 are x=6,x=-6

Find the zeros of -x^2+36=0

The zeros of -x^2+36=0 are x=6,x=-6

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- x^{2} + 36 = 0

x = 6, x = - 6

Solution steps

- x^{2} + 36 = 0

Move

36

to the right side

- x^{2} = - 36

Divide both sides by

- 1

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

8 e = 2 (e - 6)

1 < x < 6

a^{3} - 4 a

3 x^{2} - 12 x - 36

lo g_{10} (4)

What are the solutions to the equation -x^2+36=0 ?
The solutions to the equation -x^2+36=0 are x=6,x=-6
Find the zeros of -x^2+36=0
The zeros of -x^2+36=0 are x=6,x=-6