What is 1/12 (x+2)^2(x-3)^2 ?

The solution to 1/12 (x+2)^2(x-3)^2 is ((x+2)^2(x-3)^2)/(12)

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simplify 1/12 (x+2)^2(x-3)^2

simplify

\frac{1}{12} (x + 2)^{2} (x - 3)^{2}

\frac{( x + 2 ) ^{2} ( x - 3 ) ^{2}}{12}

Solution steps

\frac{1}{12} (x + 2)^{2} (x - 3)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 2)^{2} (x - 3)^{2} = ((x + 2) (x - 3))^{2}

= \frac{1}{12} ((x + 2) (x - 3))^{2}

((x + 2) (x - 3))^{2} = (x + 2)^{2} (x - 3)^{2}

= \frac{1}{12} (x + 2)^{2} (x - 3)^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( x + 2 ) ^{2} ( x - 3 ) ^{2}}{12}

Multiply:

1 \cdot (x + 2)^{2} = (x + 2)^{2}

= \frac{( x + 2 ) ^{2} ( x - 3 ) ^{2}}{12}

1.13 \cdot 1 0^{- 8}

(e^{x})^{2} ln (x)

16 r^{2} s^{2}

(3 x^{2} y^{3}) (4 x y^{8})

(3)^{\frac{1}{2}}

What is 1/12 (x+2)^2(x-3)^2 ?
The solution to 1/12 (x+2)^2(x-3)^2 is ((x+2)^2(x-3)^2)/(12)