What is (2x+1)^2(4x^2-2x+1)^2 ?

The solution to (2x+1)^2(4x^2-2x+1)^2 is (2x+1)^2(4x^2-2x+1)^2

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simplify (2x+1)^2(4x^2-2x+1)^2

simplify

(2 x + 1)^{2} (4 x^{2} - 2 x + 1)^{2}

(2 x + 1)^{2} (4 x^{2} - 2 x + 1)^{2}

Solution steps

(2 x + 1)^{2} (4 x^{2} - 2 x + 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(2 x + 1)^{2} (4 x^{2} - 2 x + 1)^{2} = ((2 x + 1) (4 x^{2} - 2 x + 1))^{2}

= ((2 x + 1) (4 x^{2} - 2 x + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (2 x + 1)^{2} (4 x^{2} - 2 x + 1)^{2}

(sec^{2} (x))^{3}

8 e^{- x}

(2 x - 2 y)^{2} (2 x + 2 y)^{2}

f^{- 1} (21)

4.9 \cdot 1 0^{- 8}

What is (2x+1)^2(4x^2-2x+1)^2 ?
The solution to (2x+1)^2(4x^2-2x+1)^2 is (2x+1)^2(4x^2-2x+1)^2