What is factor 2x^2-19x+42 ?

The solution to factor 2x^2-19x+42 is (2x-7)(x-6)

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factor 2x^2-19x+42

factor

2 x^{2} - 19 x + 42

(2 x - 7) (x - 6)

Solution steps

2 x^{2} - 19 x + 42

Break the expression into groups

= (2 x^{2} - 7 x) + (- 12 x + 42)

Factor out

x

from

2 x^{2} - 7 x : x (2 x - 7)

Factor out

- 6

from

- 12 x + 42 : - 6 (2 x - 7)

= x (2 x - 7) - 6 (2 x - 7)

Factor out common term

2 x - 7

= (2 x - 7) (x - 6)

50 r^{2} - 2

\frac{4 !}{( 4 - 1 ) ! 1 !}

5 - 52

x^{2} - 11 x - 26

\frac{532 e}{180 x ^{4}} \leq 0.0001