What is e^{-(ln(x)+1/2)} ?

The solution to e^{-(ln(x)+1/2)} is 1/(e^{\frac{2ln(x)+1){2}}}

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simplify e^{-(ln(x)+1/2)}

simplify

e^{- (l n (x) + \frac{1}{2})}

\frac{1}{e ^{\frac{2 l n ( x ) + 1}{2}}}

Solution steps

e^{- (l n (x) + \frac{1}{2})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(l n (x) + \frac{1}{2})}}

Remove parentheses:

(a) = a

= \frac{1}{e ^{l n (x) + \frac{1}{2}}}

e^{l n (x) + \frac{1}{2}} = e^{\frac{2 l n ( x ) + 1}{2}}

= \frac{1}{e ^{\frac{l n ( x ) \cdot 2 + 1}{2}}}

\frac{7}{29}

\frac{( x + 1 ) ^{6}}{x ^{6}}

3.41 \cdot 1 0^{- 3} m^{2}

(9 x y^{8}) \cdot (6 x^{5} y^{3})

What is e^{-(ln(x)+1/2)} ?
The solution to e^{-(ln(x)+1/2)} is 1/(e^{\frac{2ln(x)+1){2}}}