What is the d/(dn)((q)(5lk^2n^2)) ?

The d/(dn)((q)(5lk^2n^2)) is 10lk^2qn

What is the first d/(dn)((q)(5lk^2n^2)) ?

The first d/(dn)((q)(5lk^2n^2)) is 10lk^2qn

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\frac{d}{d n} ((q) (5 l k^{2} n^{2}))

10 l k^{2} q n

Solution steps

\frac{d}{d n} ((q) (5 l k^{2} n^{2}))

Treat

l, k, q

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= q \cdot 5 l k^{2} \frac{d}{d n} (n^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= q \cdot 5 l k^{2} \cdot 2 n^{2 - 1}

Simplify

= 10 l k^{2} q n

t e^{a t} sin (w) t

- 0.45 (42 \cdot 1 0^{- 3})

75 (0.84)^{- 4}

(x + h)^{2} x^{2} \cdot h

What is the d/(dn)((q)(5lk^2n^2)) ?
The d/(dn)((q)(5lk^2n^2)) is 10lk^2qn
What is the first d/(dn)((q)(5lk^2n^2)) ?
The first d/(dn)((q)(5lk^2n^2)) is 10lk^2qn