What is (2.08*10^{-4})(1801) ?

The solution to (2.08*10^{-4})(1801) is 0.374608

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simplify (2.08*10^{-4})(1801)

simplify

(2.08 \cdot 1 0^{- 4}) (1801)

0.374608

Solution steps

(2.08 \cdot 1 0^{- 4}) (1801)

Apply rule:

(a) = a

(1801) = 1801

= 2.08 \cdot 1 0^{- 4} \cdot 1801

Multiply the numbers:

2.08 \cdot 1801 = 3746.08

= 3746.08 \cdot 1 0^{- 4}

= 1 0^{- 4} \cdot 3746.08

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 4} = \frac{1}{1 0 ^{4}}

= \frac{1}{1 0 ^{4}} \cdot 3746.08

1 0^{4} = 10000

= \frac{1}{10000} \cdot 3746.08

\frac{1}{10000} \cdot 3746.08 = \frac{3746.08}{10000}

= \frac{3746.08}{10000}

Divide the numbers:

\frac{3746.08}{10000} = 0.374608

= 0.374608

(6.5499 x 1 0^{23}) \cdot 10

(6.7 x 1 0^{1}) (5 x 1 0^{6})

(e^{x} + 1)^{- 2}

7.07 \cdot 1 0^{- 4} \cdot 9.899

16 a^{2} b^{2} c^{2}