What is ((3x^2y^{-3})/(2x^{-3)y^2})^3 ?

The solution to ((3x^2y^{-3})/(2x^{-3)y^2})^3 is (27x^{15})/(8y^{15)}

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simplify ((3x^2y^{-3})/(2x^{-3)y^2})^3

simplify

(\frac{3 x ^{2} y ^{- 3}}{2 x ^{- 3} y ^{2}})^{3}

\frac{27 x ^{15}}{8 y ^{15}}

Solution steps

(\frac{3 x ^{2} y ^{- 3}}{2 x ^{- 3} y ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 x ^{2} y ^{- 3} ) ^{3}}{( 2 x ^{- 3} y ^{2} ) ^{3}}

Simplify

(3 x^{2} y^{- 3})^{3} : \frac{27 x ^{6}}{y ^{9}}

= \frac{\frac{27 x ^{6}}{y ^{9}}}{( 2 x ^{- 3} y ^{2} ) ^{3}}

Simplify

(2 x^{- 3} y^{2})^{3} : \frac{8 y ^{6}}{x ^{9}}

= \frac{\frac{27 x ^{6}}{y ^{9}}}{\frac{8 y ^{6}}{x ^{9}}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{27 x ^{6} x ^{9}}{y ^{9} \cdot 8 y ^{6}}

27 x^{6} x^{9} = 27 x^{15}

= \frac{27 x ^{15}}{8 y ^{9} y ^{6}}

y^{9} \cdot 8 y^{6} = 8 y^{15}

= \frac{27 x ^{15}}{8 y ^{15}}

4 + 3

x + ∣ x ∣ = 36

5 x 2 + 3 x y + 6 y 3

3 = - 6 x + 15

(- \frac{8}{9})^{2}

What is ((3x^2y^{-3})/(2x^{-3)y^2})^3 ?
The solution to ((3x^2y^{-3})/(2x^{-3)y^2})^3 is (27x^{15})/(8y^{15)}