What is ((2^{-4})^{z^{-3}})^5 ?

The solution to ((2^{-4})^{z^{-3}})^5 is 2^{-(20)/(z^3)}

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simplify ((2^{-4})^{z^{-3}})^5

simplify

((2^{- 4})^{z^{- 3}})^{5}

2^{- \frac{20}{z ^{3}}}

Solution steps

((2^{- 4})^{z^{- 3}})^{5}

(2^{- 4})^{z^{- 3}} : 2^{- \frac{4}{z ^{3}}}

= (2^{- \frac{4}{z ^{3}}})^{5}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 2^{(- \frac{4}{z ^{3}}) \cdot 5}

Simplify

(- \frac{4}{z ^{3}}) \cdot 5 : - \frac{20}{z ^{3}}

= 2^{- \frac{20}{z ^{3}}}

(θ + 1)^{3} \cdot (θ + x)^{3}

e^{- 0.25 (3.5 - 1.8)^{2}}

1.4714800000000 \dots \cdot 1 0^{- 6}

(3 x 1 0^{4}) (2.1 x 1 0^{3})

What is ((2^{-4})^{z^{-3}})^5 ?
The solution to ((2^{-4})^{z^{-3}})^5 is 2^{-(20)/(z^3)}