What are the solutions to the equation -3x^2-4x-4=0 ?

The solutions to the equation -3x^2-4x-4=0 are x=-2/3-i(2sqrt(2))/3 ,x=-2/3+i(2sqrt(2))/3

Find the zeros of -3x^2-4x-4=0

The zeros of -3x^2-4x-4=0 are x=-2/3-i(2sqrt(2))/3 ,x=-2/3+i(2sqrt(2))/3

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- 3 x^{2} - 4 x - 4 = 0

x = - \frac{2}{3} - i \frac{2 2}{3}, x = - \frac{2}{3} + i \frac{2 2}{3}

Solution steps

- 3 x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

Simplify

(- 4)^{2} - 4 (- 3) (- 4) : 42 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 4 ) - 4 2 i}{2 ( - 3 )}

x = \frac{- ( - 4 ) + 4 2 i}{2 ( - 3 )} : - \frac{2}{3} - i \frac{2 2}{3}

x = \frac{- ( - 4 ) - 4 2 i}{2 ( - 3 )} : - \frac{2}{3} + i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} - i \frac{2 2}{3}, x = - \frac{2}{3} + i \frac{2 2}{3}

\frac{x}{x + 1} \geq 2

y^{2} - 2 y - 15

\frac{1 0 ^{16}}{3125000}

- 4 x + 7 > x - 13

2 x + 3 \geq 7 or 2 x + 9 > 11

What are the solutions to the equation -3x^2-4x-4=0 ?
The solutions to the equation -3x^2-4x-4=0 are x=-2/3-i(2sqrt(2))/3 ,x=-2/3+i(2sqrt(2))/3
Find the zeros of -3x^2-4x-4=0
The zeros of -3x^2-4x-4=0 are x=-2/3-i(2sqrt(2))/3 ,x=-2/3+i(2sqrt(2))/3