What is 5(e^{-x}cos(1/2)x) ?

The solution to 5(e^{-x}cos(1/2)x) is (5cos(1/2)x)/(e^x)

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simplify 5(e^{-x}cos(1/2)x)

simplify

5 (e^{- x} cos (\frac{1}{2}) x)

\frac{5 cos ( \frac{1}{2} ) x}{e ^{x}}

Solution steps

5 (e^{- x} cos (\frac{1}{2}) x)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 5 cos (\frac{1}{2}) \frac{1}{e ^{x}} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5 cos ( \frac{1}{2} ) x}{e ^{x}}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{5 cos ( \frac{1}{2} ) x}{e ^{x}}

(a^{n} b^{m}) (a^{2} b)

\frac{x + 3}{x + 4}

4.305 x 1 0^{- 10}

\frac{e ^{x}}{x} \cdot x^{- 4}

- 200 e^{- 0.5}

What is 5(e^{-x}cos(1/2)x) ?
The solution to 5(e^{-x}cos(1/2)x) is (5cos(1/2)x)/(e^x)