What is [(b^{-3})^4]^{-2} ?

The solution to [(b^{-3})^4]^{-2} is b^{24}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify [(b^{-3})^4]^{-2}

simplify

[(b^{- 3})^{4}]^{- 2}

b^{24}

Solution steps

[(b^{- 3})^{4}]^{- 2}

(b^{- 3})^{4} : b^{- 12}

= [b^{- 12}]^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( b ^{- 12} ) ^{2}}

(b^{- 12})^{2} : b^{- 24}

= \frac{1}{b ^{- 24}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- 24} = \frac{1}{b ^{24}}

= \frac{1}{\frac{1}{b ^{24}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{24}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= b^{24}

4 (0.3718) e^{- 0.2}

\frac{( x ^{3} - 2 ) ^{6}}{x ^{6}}

(e^{j (2 x + \frac{π}{4})})^{2}

x + 3 3

55 x^{4} y^{3} x