What is the answer to (x+2)/3-(x-1)/2 =1 ?

The answer to (x+2)/3-(x-1)/2 =1 is x=1

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(x+2)/3-(x-1)/2 =1

\frac{x + 2}{3} - \frac{x - 1}{2} = 1

x = 1

Solution steps

\frac{x + 2}{3} - \frac{x - 1}{2} = 1

Multiply by LCM

2 (x + 2) - 3 (x - 1) = 6

Expand

2 (x + 2) - 3 (x - 1) : - x + 7

- x + 7 = 6

Move

7

to the right side

- x = - 1

Divide both sides by

- 1

x = 1

12 n^{3} - 48

6 x^{2} - 11 x - 2 = 0

\frac{1 5 ^{6} \cdot 1 2 ^{4} \cdot 5 ^{9} \cdot 6 ^{3}}{1 0 ^{11} \cdot 3 ^{13} \cdot 5 ^{4}}

9 x^{2} - 24 x y + 7 y^{2}

x^{2} - x = 3

What is the answer to (x+2)/3-(x-1)/2 =1 ?
The answer to (x+2)/3-(x-1)/2 =1 is x=1
Solve for x: (x+2)/3-(x-1)/2 =1
The solution is x=1