What is (1.6*10^{-19})(0.0000042) ?

The solution to (1.6*10^{-19})(0.0000042) is (21)/(3125000*10^{19)}

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simplify (1.6*10^{-19})(0.0000042)

simplify

(1.6 \cdot 1 0^{- 19}) (0.0000042)

\frac{21}{3125000 \cdot 1 0 ^{19}}

Decimal Notation

6.72 E - 25

Solution steps

(1.6 \cdot 1 0^{- 19}) (0.0000042)

Apply rule:

(a) = a

(0.0000042) = 0.0000042

= 1.6 \cdot 1 0^{- 19} \cdot 0.0000042

Multiply the numbers:

1.6 \cdot 0.0000042 = 0.00000672

= 0.00000672 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 0.00000672

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 0.00000672

\frac{1}{1 0 ^{19}} \cdot 0.00000672 = \frac{0.00000672}{1 0 ^{19}}

= \frac{0.00000672}{1 0 ^{19}}

\frac{0.00000672}{1 0 ^{19}} = \frac{672}{100000000 \cdot 1 0 ^{19}}

= \frac{672}{100000000 \cdot 1 0 ^{19}}

Factor the number:

672 = 32 \cdot 21

= \frac{32 \cdot 21}{100000000 \cdot 1 0 ^{19}}

Factor the number:

100000000 = 32 \cdot 3125000

= \frac{32 \cdot 21}{32 \cdot 3125000 \cdot 1 0 ^{19}}

Cancel the common factor:

32

= \frac{21}{3125000 \cdot 1 0 ^{19}}

(4 x^{2} y^{2}) (3 x y)

((h^{5})^{'})^{- 3}

5.9 \cdot 1 0^{- 2}

e^{- 4 x} (- e^{3 x})

2 a^{2} \cdot b^{2}

What is (1.6*10^{-19})(0.0000042) ?
The solution to (1.6*10^{-19})(0.0000042) is (21)/(3125000*10^{19)}